Let’s use the basic calculations described in previous posts about this issue:

Beta-oxidation of fatty acids with an odd number of carbons.

Energetic balance of the total (and I mean total) oxidation of a fatty acid with an odd number of carbons.

Oxidation of a fatty acid with 17 atoms of carbon.

Activation of the fatty acid to Acyl CoA = **-2 ATP**

Number of rounds in the Beta oxidation

(17/2) -1.5 = 8.5-1.5 = 7

7 rounds x 5 ATP/ round = **35 ATP**

Number of units of Acetyl CoA produced = 7 Acetyl CoA

7 Acetyl CoA x 12 ATP/Acetyl CoA = **84 ATP**

Propionyl CoA up to Succinyl CoA = **-1ATP**

Succinyl CoA up to Malate = **3 ATP**

** **

Malate up to Pyruvate (1 NADPH.H^{+})

Pyruvate up to Acetyl Co A = **3 ATP**

Acetyl CoA oxidation in the Krebs Cycle = **12 ATP**

Total of ATP (considering the total oxidation of Propionyl CoA converted to Malate and then from Malate to Pyruvate and then from Pyruvate to Acetyl CoA = -2 + 35 +84 -1 + 3 +3 +12 = 134 ATP

**In summary ** (following the equivalence of 1 NADH.H^{+} yielding 3 ATP in the Respiratory Chain and 1 FADH2 yielding 2 ATP):

-Calculate the number of rounds of the fatty acid in the Beta-oxidation:

Number of rounds = (Number of carbons/2) -1.5

-The number of Acetyl CoA is the same as the number of rounds

-Subtract 2 ATP that were used in the initial activation of the fatty acid.

-Multiply the number of rounds x 5 ATP/round.

-Multiply the number of Acetyl CoA x 12 ATP/Acetyl CoA.

-Add 17 ATP produced in the total oxidation of Propionyl CoA to CO2

To practice this kind of exercise, I suggest that you do the calculations using now the criteria that considers that each NADH.H^{+} oxidized in the Respiratory Chain yields 2.5 ATP and each FADH2 yields 1.5 ATP

**I am looking forward to see your answers and comments!!**!