Let’s use the basic calculations described in previous posts about this issue:
Beta-oxidation of fatty acids with an odd number of carbons.
Energetic balance of the total (and I mean total) oxidation of a fatty acid with an odd number of carbons.
Oxidation of a fatty acid with 17 atoms of carbon.
Activation of the fatty acid to Acyl CoA = -2 ATP
Number of rounds in the Beta oxidation
(17/2) -1.5 = 8.5-1.5 = 7
7 rounds x 5 ATP/ round = 35 ATP
Number of units of Acetyl CoA produced = 7 Acetyl CoA
7 Acetyl CoA x 12 ATP/Acetyl CoA = 84 ATP
Propionyl CoA up to Succinyl CoA = -1ATP
Succinyl CoA up to Malate = 3 ATP
Malate up to Pyruvate (1 NADPH.H+)
Pyruvate up to Acetyl Co A = 3 ATP
Acetyl CoA oxidation in the Krebs Cycle = 12 ATP
Total of ATP (considering the total oxidation of Propionyl CoA converted to Malate and then from Malate to Pyruvate and then from Pyruvate to Acetyl CoA = -2 + 35 +84 -1 + 3 +3 +12 = 134 ATP
In summary (following the equivalence of 1 NADH.H+ yielding 3 ATP in the Respiratory Chain and 1 FADH2 yielding 2 ATP):
-Calculate the number of rounds of the fatty acid in the Beta-oxidation:
Number of rounds = (Number of carbons/2) -1.5
-The number of Acetyl CoA is the same as the number of rounds
-Subtract 2 ATP that were used in the initial activation of the fatty acid.
-Multiply the number of rounds x 5 ATP/round.
-Multiply the number of Acetyl CoA x 12 ATP/Acetyl CoA.
-Add 17 ATP produced in the total oxidation of Propionyl CoA to CO2
To practice this kind of exercise, I suggest that you do the calculations using now the criteria that considers that each NADH.H+ oxidized in the Respiratory Chain yields 2.5 ATP and each FADH2 yields 1.5 ATP
I am looking forward to see your answers and comments!!!